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Hi,

Instead of simply trying to remember the words from a list, try to learn vocabulary from general reading. This is definitely time consuming but is the best way to learn vocab. Whenever you learn a new word, try to get into its usage as well. There are good books (Norman Lewis) out there which teaches vocab from contextual point of view.

All the best

Hi, though most of the US univs require you to take SAT, there are some universities which require only TOEFL score. So, the best way is to go through the websites of the universities that you intend to join and find out the admission requirements

All the best

The minimum distance between the two will be attained after they travel 5 km each. In this case the distance between them will be sqrt(50).

Assume that the distance between them will be minimum after each of them travels x km. Now we have a right angle triangle with the lengths of the perpendicular sides as x and 10 – x. So the closest distance between them is the hypotenuse and the length of this hypotenuse will be minimum at x = 5 (You can take the help of derivatives or quadratic equations basics to conclude that hypotenuse will be minimum at x = 5)

Regards

Given number is 1001001001 = 11×91000091 = 11×91 x 1000001 = 11×91 x 101×9901

Thus, the largest divisor of 1001001001 less than 10000 is 9901.

9901 divided by 7, the remainder is 3

Hi,

The answer is 3N + 1 itself.

If we multiply two odd numbers the result will be odd and not even. Just check this…

Hi,

Public Banks wage bill is (11136 – 461) i.e 10675 more than that of Foreign banks.

So the required percentage = (10675/461) x 100 = 2315.61%

Other incomes for Public banks = 7045

Interest income for Foreign banks = 4969

This ratio is close to 3 : 1 and I find no answer choice here…

Hi,

Muggu has provided his answer to this question. Dear Muggu, can you please more lucid with your explanation?

Dear coolrna,

There seems to be a problem with the solution given by you. Can you please support your answer?

Hi,

One good thing is that you are eligible for CAT (50% in graduation required) and since not all the top B-Schools give priority to your graduation percentage, you have definite chances to get into the top B-Schools provided you score high in CAT and post-CAT activities as well. So, stop worrying about the percentage factor and give your best shot in CAT.

All the best

The given series is an arithmetic series starting with 20 and with 4 as the common difference. We need to find the number of terms in this series such that their sum is more than 1000

The sum to n terms in a A.P is given by n/2(2a+ (n-1)d) where, a is the first term and d is the common difference.

So, we have n/2(40+(n-1)4) > 1000

n(2n + 18) > 1000

For n = 18, the value of n(2n+18) = 18(54) = 9(108) < 1000

For n = 19, the value of n(2n+18) = 19(56) > 1000

So after 19 years, his total savings will be more than 1000

(In fact, you can use options to conclude the answer quickly)

Hi,

Though both CAT and GMAT are online exams, they differ not only in the syllabus of the exam but also the mode. CAT is Computer Based Test and GMAT is Computer Adaptive Test. Also, the syllabus for CAT is much more than that of GMAT and one who prepares exclusively for GMAT will not be able to score high in CAT. Definitely CAT is much tougher than that of GMAT and hence one needs to put an extra amount of preparation to crack CAT

1. Given that he sells the mixture at cost price and gains 11.11% i.e. 1/9.

To gain 1/9, the selling price must be 10/9 the cost price.

Since this is not allowed, he must give 9/10 of the quantity. So the remaining 1/10 must be water.

Thus the ratio of milk and water is 9 : 1.

Thus for every 9 litres of milk he must add 1 liter of water.

Hence, for every liter of milk he must add 1/9 liter of water..this is same as 11.11%

So the simple logic is …since he is getting 11.11% this gain is purely because of water and hence this itself will be the answer.

2. Given that the number of 25 paise coins are 133.33% i.e 4/3 more than that of 1 rupee coins.

Let the number of 1 rupee coins be 3x

Then the number of 25 paise coins will be 7x

The number of 50 paise coins will be 105 – (10x)

Amount contributed by 1 rupee coins = 3x rupees = 300x paise

Amount contributed by 25 paise coins = 25(7x) = 175 paise

Amount contributed by 50 paise coins = [105-(10x)]50 = 5250 – 500x paise

Total amount is given as 50.5 rupees = 5050 paise

Thus, we have 5250 – 25x = 5050

Hence, x = 8.

Thus, the total number of 1 rupee coins = 3x = 24

Hi, we have a result that will help us to answer this.

If P is a prime number, then for any natural number n (not divisible by P) the number n^{(P-1) – 1 is exactly divisible by P.}

So the number 1516 – 1 is divisible by 17, since 17 is prime

Yes, that’s even my logic as well….any other ways folks?

Given that the vehicle is a government vehicle and it starts with 79.

So the rest two digits could be any digits from the 10 digits.

Also, since it is a government vehicle, the two alphabets must be from A,B and C.

Hence the total number of vehicles to be checked will be 10×10 x 3×3 = 900

Since each vehicle takes 10 minutes to be checked, total time taken to check 900 vehicles = 900×10 minutes = 150 hours.

So, the probability that the vehicle can be found in 3 hrs = 3/150 = 1/50

Let the four consecutive odd number be x-2 , x , x+2 and x+4

Their sum is 4x+4 = 4(x+1)

Given that this sum is divisible by 10 and the result is a perfect square.

Now if x+1 = 10, the result when 4(x+1) is divided by 10 will be 4, which is a perfect square.

But if x+ 1= 10, then the first number and the second number will not be two digit numbers.

So, let us consider the next possible value of x+1.

Now if x+1 = 10k, then the sum when divided by 10 will be 4k and for this to be a perfect square, k must be a perfect square.

Let us take k = 4.

i.e. x+1 = 40.

Now the sum will be 4(40) and this divided by 10, we get the result as 16, which is a perfect square.

Hence x = 39.

Thus, the four numbers are 37, 39, 41 and 43

Hi,

As forestflame suggested try to have a passion for the subject. Besides this if you try to correlate the concepts that you learn with their practical applications you will definitely find it interesting…so develop a sort of inquisitiveness.. Besides, this you must understand that it is relatively easy to score in this subject in JEE

By the way, please post your queries in the relevant communities so that experts can answer your queries quickly. This query must be posted in the SAT Prep Community