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Definitely this is a tough call and one should not worry too much about the IIT tag but instead consider the faculty and the infrastructure provided by these colleges

Hi, just check the reply given by me below

Hi, get Arihant publications as well…

All the best

Hi,

Most of the students started preparing for CAT from their second year of engineering and I think this will give ample time for a solid preparation. By the way, are you considering joining any coaching classes?

All the best

Definitely TES…But you need to take more tests and analyze your performance in the next 3 months. In fact you will learn a good number of concepts besides improving your test taking skills.

All the best

Hi, this question is already answered in one of the discussions started by you. Also, please post your queries in the relevant communities. All queries regarding CAT preparation must be posted in the CAT Prep community.

Enjoy Learnhubbing…

Hi,

Please be more clear on your question and also see that it is posted in the relevant community. All queries regarding CAT preparation must be posted in the CAT Prep community.

Regards

Given that 448 meters required 56×27 mandays.

Hence the remaining 552 meters requires

We need these mandays in the remaining 23 days.

Hence the number of men required =

As we have 56 men, we need another 25 men extra

Hi,

You have already asked us to give the answer that you are looking for. Then what’s the point in posting this question?

Hey…just kidding…

It is definitely possible and it all depends upon your present skills set. You can check your present test taking skills by taking a mock CAT or you can take CAT 2008 full length tests on Learnhub itself and check your performance. Based on this you can work out a study plan which will definitely escalate your chances of getting into the top B-Schools.

All the best

Dear Sumanth,

Your academic profile is definitely good to compete in the so called race of IIMs admission. But you need to perform very well in CAT and post CAT activities. The admission is given based on your academic profile, CAT and post CAT performance. So gear up for the CAT preparation and do your best in the exam.

All the best

Hi,

It is officially announced that CAT will conducted in a stretch of 10 days tentatively from Nov 29 to Dec 7 and the notification regarding the same will be announced by August 30.

There is a problem with the solution.

Since repetition is allowed, the three vowels can be chosen from 5 vowels and the rest 4 alphabets can be chosen from the remaining 21 consonants. Since the repetition is allowed, we have ways to chose the required alphabets.

Now the number of ways in which these can be rearranged depends upon the number of repetitions and hence the answer has to be much bigger.

Yes, the answer has to be 40%..that’s a typo

Hi, the answer will be 103 and the logic is already explained

Hi, you cannot apply this rule to every problem. Just check the basic divisibility rules and you will get an idea

If the price is increased by x% and then decreased by x% there would be a decrease in the price and let the decrease by y%.

Let P be the original price of the article.

Given that y%(P) = 180….......(1)

Now the current price is P – 180 and this price is further reduced by y%

Given that y%(P – 180) = 153…...(2)

From (1) and (2), we get y = 15

Thus we have 15%(P) = 180

Hence P = 1200.

Definitely they must have considered the facilities that enhance the study rather than campus. Faculty must the core concern for these students….

6174 is known as Kaprekar’s constant after the Indian mathematician D. R. Kaprekar. This number is notable for the following property:

1. Take any four-digit number with at least two digits different. (Leading zeros are allowed.)

2. Arrange the digits in ascending and then in descending order to get two four-digit numbers, adding leading zeros if necessary.

3. Subtract the smaller number from the bigger number.

Go back to step 2.

The above operation, known as Kaprekar’s operation, will always reach 6174 in at most 7 steps and it stops there. Once 6174 is reached, the process will keep yielding 7641 – 1467 = 6174.

For example, choose 3524:

5432 – 2345 = 3087

8730 – 0378 = 8352

8532 – 2358 = 6174

The only four-digit numbers for which this function does not work are repdigits such as 1111, which give the answer 0 after a single iteration. All other four-digits numbers work if leading zeros are used to keep the number of digits at 4:

2111 – 1112 = 0999

9990 – 0999 = 8991 (rather than 999 – 999 = 0)

9981 – 1899 = 8082

8820 – 0288 = 8532

8532 – 2358 = 6174

495 has the same property for three-digit numbers. For five-digit numbers and above, the function does not settle down to a single value, but instead cycles through one of several series of values.

Source: Wikipedia

Hi,

The above list refers to the top AIEEE colleges. Just check it please…

Text Books: For solving problems and understanding basics

Concept of Physics Volume 1 & Volume 2, By H C Verma

Problems in General Physics, By I.E. Irodov (For selected problems)

Reference Books: For understanding doubts

Fundamentals of Physics, By Halliday, Resnick & Walker

The Feynman Lectures on Physics Volume 1 & Volume 2, By R.P. Feynman (Very nice book, all the fundamentals are well emphasized.)